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Investigating Forces & Motion
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Investigating Forces and Motion (1998)(Granada Learning).iso
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topic1
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1998-02-10
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48 lines
[general]
[page1]
type:2
caption:\
The four strips of ticker tape below were produced by different kinds \
of motion. Drag the arrows to match the descriptions of the motion to \
the ticker tapes. The motion of the tape was from right to left, so \
the left-most dot is the first one plotted.<p>
feedback:\
Correct. Equally spaced dots correspond to constant velocity motion. \
Dots getting further apart correspond to positive acceleration. Dots \
getting closer together correspond to negative acceleration.<p>
target:1ex1c, 1ex1b, 1ex1a, 1ex1d
source:1ex1a1, 1ex1d1, 1ex1c1, 1ex1b1
[page2]
type:0
caption:\
In a 100 m race the winning time was 11 s. What was the average speed \
for the whole race?<p>\
To calculate average speed you must use the formula that gives the \
average speed in terms of the two quantities given, distance and \
time.<p>\
<center> <img src="r1ex2" align=center><p>\
<center>= 100/11</center><p>\
<center>= 9.1 m/s</center><p>\
</center> Notice that since the figures in the problem (11 s and 100 \
m) have a minimum of two significant figures your answer should be \
rounded to two significant figures also.<p>
[page3]
type:0
caption:\
If the winner reached a maximum speed of 12 m/s after 4.0 seconds what \
was the athlete's average acceleration during the first 4.0 seconds of \
the race? To calculate the acceleration you must remember that \
acceleration is given by:<p>\
<img src="r1ex2b" align=center><p>\
Since the race is run in a straight line the size of the velocity \
change is the same as the speed change.<p>\
Speed change = final speed - initial speed = 12 - 0.0 = 12 m/s \
and,<p>\
<img src="r1ex2a" align=center><p>\
<center>= 12/4.0</center><p>\
<center>= 3.0 m/s<sup>2</sup>.</center><p>